strval

(PHP 4, PHP 5, PHP 7, PHP 8)

strval — 获取变量的字符串值

描述

strval ( mixed $var ) : string

返回 var 的 string 值。 参见 string 文档获取更多关于字符串转换的信息。

var 可以是任何标量类型。不能将 strval() 用于数组或对象。

参见 floatval()、intval()、settype() 和类型戏法。

User Contributed Notes

Mark Clements 02-Jun-2016 01:17
Some notes about how this function has changed over time, with regards the following statement:

> You cannot use strval() on arrays or on objects that
> do not implement the __toString() method.

== Arrays ==

In PHP 5.3 and below, strval(array(1, 2, 3)) would return the string "Array" without any sort of error occurring.

From 5.4 and above, the return value is unchanged but you will now get a notice-level error: "Array to string conversion".

== Objects ==

For objects that do not implement __toString(), the behaviour has varied:

PHP 4: "Object"
PHP 5 < 5.2: "Object id #1" (number obviously varies)
PHP >= 5.2: Catchable fatal error:  Object of class X could not be converted to string
Hayley Watson 21-Aug-2007 08:53
As of PHP 5.2, strval() will return the string value of an object, calling its __toString() method to determine what that value is.
NyctoFixer at gmail dot com 11-Jun-2007 12:19
As of PHP 5.1.4 (I have not tested it in later versions), the strval function does not attempt to invoke the __toString method when it encounters an object. This simple wrapper function will handle this circumstance for you:

<?

/**
 * Returns the string value of a variable
 *
 * This differs from strval in that it invokes __toString if an object is given
 * and the object has that method
 */
function stringVal ($value)
{
    // We use get_class_methods instead of method_exists to ensure that __toString is a public method
    if (is_object($value) && in_array("__toString", get_class_methods($value)))
        return strval($value->__toString());
    else
        return strval($value);
}

?>
kendsnyder+phpnet at gmail dot com 01-Jun-2007 10:08
The only way to convert a large float to a string is to use printf('%0.0f',$float); instead of strval($float); (php 5.1.4).

// strval() will lose digits around pow(2,45);
echo pow(2,50); // 1.1258999068426E+015
echo (string)pow(2,50); // 1.1258999068426E+015
echo strval(pow(2,50)); // 1.1258999068426E+015

// full conversion
printf('%0.0f',pow(2,50)); // 112589906846624
echo sprintf('%0.0f',pow(2,50)); // 112589906846624
portos_ze_retour at hotmail dot fr 10-Mar-2006 08:15
In complement to Tom Nicholson's contribution, here is the french version (actually it's possible to change the language, but you should check the syntax ;) )

function int_to_words($x) {
   global $nwords;

   if(!is_numeric($x))
     $w = '#';
   else if(fmod($x, 1) != 0)
     $w = '#';
   else {
     if($x < 0) {
         $w = $nwords['minus'].' ';
         $x = -$x;
     } else
         $w = '';
     // ... now $x is a non-negative integer.

     if($x < 21)  // 0 to 20
         $w .= $nwords[$x];
     else if($x < 100) {  // 21 to 99
         $w .= $nwords[10 * floor($x/10)];
         $r = fmod($x, 10);
         if($r > 0)
           $w .= '-'. $nwords[$r];
     } else if($x < 1000) {  // 100 to 999
         $w .= $nwords[floor($x/100)] .' '.$nwords['hundred'];
         $r = fmod($x, 100);
         if($r > 0)
           $w .= ' '.$nwords['separator'].' '. int_to_words($r);
     } else if($x < 1000000) {  // 1000 to 999999
         $w .= int_to_words(floor($x/1000)) .' '.$nwords['thousand'];
         $r = fmod($x, 1000);
         if($r > 0) {
           $w .= ' ';
           if($r < 100)
               $w .= $nwords['separator'].' ';
           $w .= int_to_words($r);

         }
     } else {    //  millions
         $w .= int_to_words(floor($x/1000000)) .' '.$nwords['million'];
         $r = fmod($x, 1000000);
         if($r > 0) {
           $w .= ' ';
           if($r < 100)
               $word .= $nwords['separator'].' ';
           $w .= int_to_words($r);
         }
     }
   }
   return $w;
}

 // Usage in English
$nwords = array( "zero", "one", "two", "three", "four", "five", "six", "seven",
                   "eight", "nine", "ten", "eleven", "twelve", "thirteen",
                   "fourteen", "fifteen", "sixteen", "seventeen", "eighteen",
                   "nineteen", "twenty", 30 => "thirty", 40 => "forty",
                   50 => "fifty", 60 => "sixty", 70 => "seventy", 80 => "eighty",
                   90 => "ninety" , "hundred" => "hundred", "thousand"=> "thousand", "million"=>"million",
                   "separator"=>"and", "minus"=>"minus");

echo 'There are currently '. int_to_words(-120223456) . ' members logged on.<br>';

 //Utilisation en Francais
$nwords = array( "zéro", "un", "deux", "trois", "quatre", "cinq", "six", "sept",
                   "huit", "neuf", "dix", "onze", "douze", "treize",
                   "quatorze", "quinze", "seize", "dix-sept", "dix-huit",
                   "dix-neuf", "vingt", 30 => "trente", 40 => "quarante",
                   50 => "cinquante", 60 => "soixante", 70 => "soixante-dix", 80 => "quatre-vingt",
                   90 => "quatre-vingt-dix" , "hundred" => "cent", "thousand"=> "mille", "million"=>"million",
                   "separator"=>"", "minus"=>"moins");

echo 'Il y a actuellement '. int_to_words(-120223456) . ' membres connectés.<br>';
php at ianco dot co dot uk 07-Oct-2005 04:36
I can't help being surprised that

(string)"0" == (string)"0.00"

evaluates to true. It's the same with strval and single quotes.
=== avoids it.

Why does it matter? One of my suppliers, unbelievably, uses 0 to mean standard discount and 0.00 to mean no discount in their stock files.
Steve Ball 08-Sep-2005 07:18
It seems that one is being treated as an unsigned large int (32 bit), and the other as a signed large int (which has rolled over/under).

2326201276 - (-1968766020) =  4294967296.
Tom Nicholson 28-Apr-2004 09:13
If you want to convert an integer into an English word string, eg. 29 -> twenty-nine, then here's a function to do it.

Note on use of fmod()
  I used the floating point fmod() in preference to the % operator, because % converts the operands to int, corrupting values outside of the range [-2147483648, 2147483647]

I haven't bothered with "billion" because the word means 10e9 or 10e12 depending who you ask.

The function returns '#' if the argument does not represent a whole number.

<?php
$nwords = array( "zero", "one", "two", "three", "four", "five", "six", "seven",
                   "eight", "nine", "ten", "eleven", "twelve", "thirteen",
                   "fourteen", "fifteen", "sixteen", "seventeen", "eighteen",
                   "nineteen", "twenty", 30 => "thirty", 40 => "forty",
                   50 => "fifty", 60 => "sixty", 70 => "seventy", 80 => "eighty",
                   90 => "ninety" );

function int_to_words($x) {
   global $nwords;

   if(!is_numeric($x))
      $w = '#';
   else if(fmod($x, 1) != 0)
      $w = '#';
   else {
      if($x < 0) {
         $w = 'minus ';
         $x = -$x;
      } else
         $w = '';
      // ... now $x is a non-negative integer.

      if($x < 21)   // 0 to 20
         $w .= $nwords[$x];
      else if($x < 100) {   // 21 to 99
         $w .= $nwords[10 * floor($x/10)];
         $r = fmod($x, 10);
         if($r > 0)
            $w .= '-'. $nwords[$r];
      } else if($x < 1000) {   // 100 to 999
         $w .= $nwords[floor($x/100)] .' hundred';
         $r = fmod($x, 100);
         if($r > 0)
            $w .= ' and '. int_to_words($r);
      } else if($x < 1000000) {   // 1000 to 999999
         $w .= int_to_words(floor($x/1000)) .' thousand';
         $r = fmod($x, 1000);
         if($r > 0) {
            $w .= ' ';
            if($r < 100)
               $w .= 'and ';
            $w .= int_to_words($r);
         }
      } else {    //  millions
         $w .= int_to_words(floor($x/1000000)) .' million';
         $r = fmod($x, 1000000);
         if($r > 0) {
            $w .= ' ';
            if($r < 100)
               $word .= 'and ';
            $w .= int_to_words($r);
         }
      }
   }
   return $w;
}

?>

Usage:
<?php
echo 'There are currently '. int_to_words($count) . ' members logged on.';
?>